Help with a Primary Standard Equation

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The discussion revolves around the need to formulate a chemical equation for the reaction between potassium biphthalate and sodium hydroxide in aqueous solution, aimed at standardizing sodium hydroxide. The user expresses difficulty in deriving the equation for this reaction. Additionally, there are inquiries about calculating water hardness and determining EDTA levels in water, indicating a broader interest in water chemistry. The conversation shifts focus after the user acknowledges a mistake in posting and seeks to address the topic of water hardness instead. Overall, the thread highlights the need for clarity in chemical equations and water quality assessments.
SolidSnake
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I can't seem to get an equation for this reaction.Potassium Biphthlate + Sodium Hydroxide give me what? Both are dissolved in water. Need to figure out the equation to standardize the sodium hydroxide.

NaOH + KHC8H4O4 -->All are aqueous.

EDIT: read the sticky right after posting, sorry will post in the other section delete pls.
 
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determination of EDTA in water

Hardness of water


how can we calculate the Hardness of water please give detailed calculation
thanks
jani
 
jani said:
Hardness of water


how can we calculate the Hardness of water please give detailed calculation
thanks
jani
determinition of the EDTA in water
 
Thread 'Confusion regarding a chemical kinetics problem'

Thread 'Confusion regarding a chemical kinetics problem'

TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
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