What mistake did I make in finding the net force on a rotating disc?

In summary, a horizontal disc rotating at an angular velocity w has a small body of mass m moving with velocity v relative to the disc along the diameter. The net force exerted by the disc on the body can be found as a function of radius from the centre using the expression (v^2+(wr)^2)^(1/2). However, this only represents the speed of the particle and not the velocity, which is a vector quantity. The acceleration takes into account both the change in speed and direction of velocity, which can be found using the equation (4) in the provided resource.
  • #1
Brilli
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Homework Statement


A horizontal disc is rotating with an angular velocity w about its axis perpendicular to its plane. A small body of mass m moves with velocity v relative to the disc alog the diameter. Find the net force exerted by the disk on the body as function of radius from centre.

Homework Equations

The Attempt at a Solution


Attepmt-the velocity component perpendicular to radius is wr and its normal component is v. Thus net velocity at radius r is (v^2+(wr)^2)^(1/2).
I differentiate it wrt time but the answer comes to be wrong. Could anyone point out my mistake?
 
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  • #2
Brilli said:
Thus net velocity at radius r is (v^2+(wr)^2)^(1/2).
I differentiate it wrt time but the answer comes to be wrong. Could anyone point out my mistake?
The expression (v2+(wr)2)1/2 represents the speed of the particle, not the velocity. Velocity is a vector quantity.
Acceleration is defined as rate of change of velocity, not rate of change of speed. So, acceleration takes into account change in direction of velocity as well as change in speed.

For a review of velocity and acceleration in polar coordinates, see
https://ocw.mit.edu/courses/aeronau...fall-2009/lecture-notes/MIT16_07F09_Lec05.pdf

Note equation (4), which gives the acceleration.
 
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