Help with Circuit Nodal Analysis

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SUMMARY

The discussion focuses on performing nodal analysis to determine voltages in a circuit. The user initially encounters discrepancies between hand calculations and simulation results. Key corrections include adjusting the coefficient of the VA term to -0.001 and the Vout term to 0.0025 in the equations. Additionally, multiplying through by 10,000 simplifies calculations by converting coefficients to integers, enhancing accuracy in nodal analysis.

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  • Understanding of nodal analysis in electrical circuits
  • Familiarity with voltage division principles
  • Basic algebra skills for manipulating equations
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  • Review the principles of nodal analysis in electrical engineering
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  • Learn techniques for simplifying circuit equations
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Electrical engineering students, circuit designers, and anyone involved in analyzing and simulating electrical circuits.

ethanh100
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Summary: Perform nodal analysis on a circuit to find voltages.

For a laboratory I am trying to find the nodal voltages for a circuit we built using hand calculations. I have the answer as we ran the simulation which shows all the nodal voltages, however my nodal analysis seems to be wrong as I am getting completely different values. In the circuit I am combining nodes Vout+ and Vout- into one node to make it a bit simpler, so putting RL and R5 together as a 2k ohm, and then I can just do voltage division later to find Vout-. So I am solving for Va, Vb and Vout. Can someone explain to me what i am doing wrong.. Thank you!

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You set it up right, you just made a mistake in your bottom equation. The coefficient of the VA term should be -0.001, and the coefficient of the Vout term should be 0.0025. If you correct those, you get the same answer as in the plot. By the way, it is a lot easier to do the math if you multiply through by 10,000 so all of the coefficients are integers.
 
Ah okay thank you, I always seem to mess up the signs and algebra in nodal analysis. Youre right it would likely be a lot easier if I just multiplied to a common base. Thank you!
 

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