- #1
Jay9313
- 40
- 0
Homework Statement
[itex]\frac{dy}{dx}[/itex]=3y f(2)=-1
and
[itex]\frac{dy}{dx}[/itex]=e[itex]^{y}[/itex]x when x=-2 y=-ln(3)
I'm in Calc AB By the way, so please do not try to show me methods that are too advanced.
Homework Equations
There are no relevant equations?
The Attempt at a Solution
My attempt at the first solution is
[itex]\int[/itex][itex]\frac{dy}{3y}[/itex]=[itex]\int[/itex]dx
[itex]\frac{ln(y)}{3}[/itex]=x+c
y=e[itex]^{3x+3c}[/itex]
ln(-1)=6+3c
You can't have that Natural Log though.. So I 'm stuck.
My attempt at the second solution is..
∫[itex]\frac{dy}{e^{y}}[/itex]=∫x dx
-[itex]\frac{1}{e^{y}}[/itex]=[itex]\frac{x^{2}}{2}[/itex]+c
-ln(e[itex]^{-y}[/itex])=e[itex]^{}\frac{x^{2}+2c}{2}[/itex]
-ln(3)=e[itex]^{}\frac{4+2c}{2}[/itex]
Last edited: