Help with energy momentum relation.

randombill
Messages
81
Reaction score
0
Hi,

I needed to derive a few equations using relativistic kinematics and I needed help with this simple equation.

attachment.png


Basically I need to write the p^2c^2 part in terms of mass and c, in other words, what is p equal to without E being in the equation?
 

Attachments

  • 5d994dc6c8e5b2e5b8d63802278fd374.png
    5d994dc6c8e5b2e5b8d63802278fd374.png
    559 bytes · Views: 554
Physics news on Phys.org
p=m0*v/Sqrt[1-v^2/c^2], m0 is the rest mass.

For anything more, you'll have to let us know where you're trying to get to (i.e. the equations you want to derive).
 
timthereaper said:
p=m0*v/Sqrt[1-v^2/c^2], m0 is the rest mass.

For anything more, you'll have to let us know where you're trying to get to (i.e. the equations you want to derive).

Sure,

I http://hyperphysics.phy-astr.gsu.edu/hbase/relativ/relmom.html" that (pc)2 = (mc2)2 - (mo2c4)



So would this be correct?

E = ((moc2)2 + (mc2)2 - (mo2c4))1/2
 
Last edited by a moderator:
randombill said:
So would this be correct?

E = ((moc2)2 + (mc2)2 - (mo2c4))1/2

Yes, but it doesn't say anything really new. The first and last terms in that equation cancel. After you do that, what do you have left? :smile:
 
<br /> E=\gamma m_0c^2<br />
and
<br /> (pc)^2=E^2-(m_0 c^2)^2<br />
Make the appropriate substitution.
 
Thanks for the help thus far. The page I'm looking at is http://teachers.web.cern.ch/teachers/archiv/hst2002/bubblech/mbitu/applications_of_special_relativi.htm" and I'm trying to derive the general equation for an elastic collision. So far I have the following solved, please check my math. It's a little blurry, sorry!

attachment.php?attachmentid=37377&stc=1&d=1311222833.jpg
 

Attachments

  • IMG_5915.jpg
    IMG_5915.jpg
    30.4 KB · Views: 641
Last edited by a moderator:
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Back
Top