How Do Friction and Inclination Affect Rock Movement on a Hill?

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The discussion focuses on the dynamics of rocks sliding on a hill inclined at 36 degrees, with an initial speed of 12 m/s and specific coefficients of friction. The first part of the problem involves calculating the acceleration of the rocks as they slide up the hill, which is determined to be 2.19 m/s². The second part questions whether the rocks will remain at the highest point or slide back down, prompting a consideration of the forces acting on the rocks, including gravity and friction. Participants emphasize the importance of drawing a free-body diagram to analyze the direction of forces and clarify the equations used. The conversation highlights the need to reassess the equations based on the direction of motion and forces involved.
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Some sliding rocks approach the base of a hill with a speed of 12 m/s. The hill rises at 36 degrees above the horizontal and has coefficients of kinetic and static friction of .45 and .65, respectively, with these rocks. Start each part of your solution to this problem with a free-body diagram. (a) Find the acceleration of the rocks as they slide up the hill. (b) Once a rock reaches the highest point, will it stay there or slide downhill? If it stays there, show hy. If it slides down, find its acceleration on the way down.



Homework Equations

a(x)=g(sin(degrees)-(kinetic coefficient)(cos degrees)) ?



The Attempt at a Solution

acceleration= 9.8 (.22)
=2.19 m/s^2

Not sure, how to do the second part, or whether my answer to the first part is right. Thanks for any help.
 
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Anyone?
 
SoulInNeed said:

Homework Equations

a(x)=g(sin(degrees)-(kinetic coefficient)(cos degrees)) ?
The rocks are sliding in the uphill direction. Look at your free-body diagram (I am assuming you drew one, if not then please do draw one :smile:) and answer this: do the two force components, mg·sinθ and the friction force, act in the same direction or in opposite directions? I.e., do they point uphill or downhill, or does one point uphill while the other points downhill?

Would this change the equation you have written above?
 
Well, for something going downhill, that's the equation, so I thought it would work the same way going uphill, no?
 
No. Draw the free-body diagram. Think carefully about the direction of the friction force.
 
Is it a(x)=-g(u(k)cos(degrees)+sin(degrees))?
 
Bump.
 
SoulInNeed said:
Is it a(x)=-g(u(k)cos(degrees)+sin(degrees))?
Yes.
 
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