Help with periods and oscilation *and* wavelengths

AI Thread Summary
The discussion revolves around calculating the speed and period of water waves in a shallow dish, given a wavelength of 6.0 cm and a frequency of 4.8 oscillations per second. The speed of the waves is calculated using the equation speed = wavelength x frequency, resulting in 0.288 m/s after converting units to meters. The period is determined using the relationship frequency = 1/period, leading to a period of approximately 0.2083 seconds. Participants emphasize the importance of unit conversion and algebraic manipulation to solve the problem accurately. Understanding these concepts is crucial for correctly applying the equations in physics.
Sonny18n
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Homework Statement



Water waves in a shallow dish are 6.0 cm long. At one point the water oscillates up and down at a rate of 4.8 oscillations per second.
a. What is the speed of the water waves?
b. What is the period of the water waves?

Homework Equations


frequency = 1/period
Speed = wavelength x frequency

The Attempt at a Solution


Guessing 6.0 cm is thr wavelength but that wouldn't help much since I'm looking for the period and I don't even know what oscillations are.
 
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Sonny18n said:

Homework Statement



Water waves in a shallow dish are 6.0 cm long. At one point the water oscillates up and down at a rate of 4.8 oscillations per second.
a. What is the speed of the water waves?
b. What is the period of the water waves?

Homework Equations


frequency = 1/period
Speed = wavelength x frequency

The Attempt at a Solution


Guessing 6.0 cm is thr wavelength but that wouldn't help much since I'm looking for the period and I don't even know what oscillations are.

You show a relevant equation for calculating the speed from the wavelength and frequency. You are given both in the problem statement.

Be sure to be careful with your units. You should convert everything into MKS units for this problem.
 
berkeman said:
You show a relevant equation for calculating the speed from the wavelength and frequency. You are given both in the problem statement.

Be sure to be careful with your units. You should convert everything into MKS units for this problem.
Do I convert the 6.0 cm to meters because its wavelength? I don't understand what 4.8 oscillations a second translates into frequency or speed
 
Sonny18n said:
Do I convert the 6.0 cm to meters because its wavelength? I don't understand what 4.8 oscillations a second translates into frequency or speed

Yes, convert 6cm into meters, so you can calculate the speed.

When they say 4.8 oscillations per second, that is the same as saying that the frequency is 4.8Hz. Hz is "Hertz", and is equal to one oscillation per second. You write the units of Hz as 1/s. Try to always carry along the units for each quantity in your calculations, and cancel them when you have the same units in the numerator and denominator of a fraction. That helps you to use units to check your calculations.
 
berkeman said:
Yes, convert 6cm into meters, so you can calculate the speed.

When they say 4.8 oscillations per second, that is the same as saying that the frequency is 4.8Hz. Hz is "Hertz", and is equal to one oscillation per second. You write the units of Hz as 1/s. Try to always carry along the units for each quantity in your calculations, and cancel them when you have the same units in the numerator and denominator of a fraction. That helps you to use units to check your calculations.
So it would be 0.288m/s?
And for b) is the answer 4.8s?
 
Sonny18n said:
So it would be 0.288m/s?
And for b) is the answer 4.8s?

Yes on the first one -- v = 0.06m * 4.8Hz = 0.288m/s.

On the 2nd one, they have given you the frequency as 4.8Hz. Use your other equation to figure out the period that is associated with that frequency...
 
berkeman said:
Yes on the first one -- v = 0.06m * 4.8Hz = 0.288m/s.

On the 2nd one, they have given you the frequency as 4.8Hz. Use your other equation to figure out the period that is associated with that frequency...
But I'm looking for period and I only have frequency and the number "1".
 
Sonny18n said:
But I'm looking for period and I only have frequency and the number "1".

Sonny18n said:
frequency = 1/period

What does that relevant equation mean? What does it mean to take 1/anything? What is 1/2? What is 1/10? :smile:
 
berkeman said:
What does that relevant equation mean? What does it mean to take 1/anything? What is 1/2? What is 1/10? :smile:
Are you asking me to divide 1 by so and so? I don't know what that so and so is.
 
  • #10
Sonny18n said:
Are you asking me to divide 1 by so and so? I don't know what that so and so is.

If frequency = 1/period, and you have the frequency and want to find the period, what simple algebraic manipulation do you use to get the equation for period in terms of frequency?
 
  • #11
berkeman said:
If frequency = 1/period, and you have the frequency and want to find the period, what simple algebraic manipulation do you use to get the equation for period in terms of frequency?
Okay just realized where you were going with the last hint. It's probably incredible simple but I draw a blank as to what 1 can be divided to get a number as big as 4.8
 
  • #12
Sonny18n said:
Okay just realized where you were going with the last hint. It's probably incredible simple but I draw a blank as to what 1 can be divided to get a number as big as 4.8

Just to review some algebra...

If y = 1/x, and you are given y, how do you solve for x?
 
  • #13
berkeman said:
Just to review some algebra...

If y = 1/x, and you are given y, how do you solve for x?
I would've thought it was to multily y and 1 to get 4.8 but 1 divided by 4.8 clearly isn't 4.8
 
  • #14
Sonny18n said:
I would've thought it was to multily y and 1 to get 4.8 but 1 divided by 4.8 clearly isn't 4.8

Stick with my more general algebra example for a bit. In algebra, we manipulate equations to change there form in order to get to our answer. As long as we do the same thing to both sides of an equation, the equality still holds. We can add the same number to both sides, for example. Or we can multiply both sides by the same constant, or by the same variable.

What can you do to this equation: y = 1/x

To get it into the forum of x = f(y), where (y) is some function of y that you got to by a couple manipulations of the original equation?
 
  • #15
berkeman said:
Stick with my more general algebra example for a bit. In algebra, we manipulate equations to change there form in order to get to our answer. As long as we do the same thing to both sides of an equation, the equality still holds. We can add the same number to both sides, for example. Or we can multiply both sides by the same constant, or by the same variable.

What can you do to this equation: y = 1/x

To get it into the forum of x = f(y), where (y) is some function of y that you got to by a couple manipulations of the original equation?
Okay so I was messing with the numbers and divided 1 by 4.8. Then I got 0.2083 to which I divided it to 1 and got 4.8
 
  • #16
Sonny18n said:
Okay so I was messing with the numbers and divided 1 by 4.8. Then I got 0.2083 to which I divided it to 1 and got 4.8

Please answer my question in Post #14. Just blindly manipulating equations is pointless. Please use real algebra, and write out each step...
 
  • #17
berkeman said:
Please answer my question in Post #14. Just blindly manipulating equations is pointless. Please use real algebra, and write out each step...
Well it works with 2 as well. 1/2 is .5 and .5 goes into one 2 times.
 
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