Help with Problem 25 and Other Math Problems

  • Thread starter Thread starter EggNest
  • Start date Start date
AI Thread Summary
The discussion centers on solving math problems, particularly problem 25, which involves finding the length of the sides of a square given its diagonal. Participants suggest using Pythagoras' theorem to establish the relationship between the sides and the diagonal, confirming that the diagonal is the hypotenuse. The calculations indicate that the area of the square should be derived from the equation a^2 = 225/2, leading to a potential correction of previous answers. Additionally, there is a brief mention of using the law of sines for another problem. The conversation emphasizes the importance of accurate calculations and understanding geometric principles.
EggNest
Messages
4
Reaction score
0
Hello everyone,

I need help with a couple of problems, right now I'm focusing on number 25.

http://img24.exs.cx/img24/2291/probs.gif

Also, if any of you have time, could you please tell me if I have missed any so far. Thanks.

22. A= 3768.2 units^2
23. A= 25.3 units^2
24. A= 5.4 units^2

And now if I could just get some help with the others...
 
Physics news on Phys.org
Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
 
arildno said:
Now, you've got a square with the diagonal given, right?
So, what's your problem, exactly?
I need help going about finding the length of the sides
 
Sure enough, but:
1) You've got a square, right?
So, how does then the vertical side compare in length to the horizontal side?
2) Try to set up Pythagoras' theorem with the diagonal as the hypotenuse..
 
The length of all the sides would be 7.5 sqrt(2) right?
 
We have C from Pythagoras' therom
a^2 + b^2 = c^2

however for a square
a=b

so
a^2 + a^2 = c^2
2a^2=c^2

2a^2=15^2
2a^2=225


since area of a square is just a*b and a=b
area equals a*a or a^2 so divide the two out
a^2=\frac{225}{2}
 
I believe 22 is wrong
23 is right rounded
24 is right rounded
 
Last edited:
22. by law of sines

\frac {73}{\sin{\theta}}=\frac{x}{\sin{\theta}}

therefore must also be 73
73*73*.5 = 2664.5
 
Back
Top