Help with quantum problem (gravitational field)

eku_girl83
Messages
89
Reaction score
0
I need to find the energy spectrum for the energes of photons that end up in the 1st excited state from a neutron in a gravitational field of strength g (9.8). I suppose first I need to find an expression for U(x) and substitue into the Schrodinger equation? How do I know U(x)? We have been using Airy functions in class -- how do I apply these here?

I guess I just need someone to get me started on this one with a hint or two!
 
Physics news on Phys.org
To find the energy levels of a particle in a gravitational field, you must solve the Schrodinger equation with the appropriate potential. Now I know you know what the potential energy of a particle in a gravitational field is. Don't think too hard, this is basic classical mechanics. The connection to Airy functions comes from looking at the differential equation they solve and comparing it to the Schrodinger equation you have written down. Do you notice any similarities?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top