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distance betwen two charges is doubled and one charge is doubled and the other is trippled how do I set this up mathmatically

I understand that when distance doubles (r) then the effect on net charge is .25 of original F

also

I understand that the force betwen charges when increased as mentioned above, there will the force will increase by 6X

Im thinking simply the answer is 6X the force X .25 but there must be a way to relate the formulas Fe = 1/r^2 and Fe = q1q2/r^2 to show this

If I knew what r was then I could use Fe = kq1q2/r^2

Im worried this is a mathmatical problem and not that I dont understand the theory behind the physics.

any help??

will it end up something like

F = (9.0 X 10^9N*m^2/C^2) X 6(6.0X10^-8 N) / 4

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# Help with question

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