Help with Resistance Homework: Finding Sum to Infinity

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The problem involves a convergent geometric progression (g.p.) with a first term of 3, where the sum of the first five terms is twice the sum of the first ten terms. The correct formulas for the sums are S(5) = 3(r^5 - 1)/(r - 1) and S(10) = 3(r^10 - 1)/(r - 1). Setting up the equation based on the given condition leads to a solvable equation for the common ratio r. After determining r, the sum to infinity can be calculated using the formula S = a / (1 - r). The final result for the sum to infinity is 8.8, although there is confusion regarding an alternative answer of 1.60.
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Homework Statement


The first term of a convergent g.p is 3. The sum of the first five terms of the progression is twice the sum of the first ten terms. Find the sum to infinity of the progression.


Homework Equations



S(5)= 3(r^5 -1)/4
S(10)=3(r^10 -1)/9
.
.
.
8^10-9r^5+1=0
Sum to infinity= 8.8

The Attempt at a Solution


But the answer is 1.60
 
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How did you get

S_5=\frac{3\left(r^5-1\right)}{4}

It should be,

S_5=\frac{3\left(r^5-1\right)}{r-1}

Firstly set up your summations correctly, and use the info that is given - mainly:

The sum of the first five terms of the progression is twice the sum of the first ten terms.

This should give you an equality in r, which can then be solved. Then use the infinite summation formula.
 
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