Help with Science calculations please

AI Thread Summary
The discussion revolves around calculating the heat released when 500g of water vapor condenses, using a latent heat of condensation of 600 cal/g, resulting in a total of 300,000 calories released. Participants clarify that this energy will heat the surrounding air, which has a mass of 100kg. The specific heat of dry air at sea level is given as 0.24 cal/(g x °C), prompting a calculation to determine how much the air temperature will increase. The concept of heat balance is introduced, emphasizing the need to understand how energy transfer affects temperature change. Overall, the focus is on applying the correct formulas to solve the problem effectively.
glori1988
Messages
2
Reaction score
0

Homework Statement


Suppose that 500g of water vapor condense to make a cloud about the size of an average room. If we assume that the latent heat of condensation is 600cal/g, how much heat would be released to the air?

If the total mass of air before condensation is 100kg, how much warmer would the air be after condensation? Assume that the air is not undergoing any pressure changes, and use the specific heat of dry air at sea level 0.24 cal/(g x oC).


Homework Equations


I don't really know the formula to calculate


The Attempt at a Solution


I times 500*600=300,000
 
Physics news on Phys.org
glori1988 said:

Homework Statement


Suppose that 500g of water vapor condense to make a cloud about the size of an average room. If we assume that the latent heat of condensation is 600cal/g, how much heat would be released to the air?

If the total mass of air before condensation is 100kg, how much warmer would the air be after condensation? Assume that the air is not undergoing any pressure changes, and use the specific heat of dry air at sea level 0.24 cal/(g x oC).


Homework Equations


I don't really know the formula to calculate


The Attempt at a Solution


I times 500*600=300,000

That looks alright. 300,000 calories.

0.24 cal of energy heats 1 g of gas by 1 deg. How much will 300,000 cal heat 100 kg of gas?
 
I don't get your question.
 
Do you know what heat balance is?
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top