Help with Set questions please

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Homework Help Overview

The discussion revolves around a set theory problem involving the set A = (-1, -2, 1, 2, 3, 5) and asks participants to list members of two sets defined by fractions formed from elements of A. The first set includes all possible fractions (x ∈ R) and the second set includes only those fractions that simplify to integers (x ∈ Z).

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss generating fractions from elements of set A, questioning whether the results need to be members of A and exploring the implications of forming fractions with both the numerator and denominator from A.

Discussion Status

Some guidance has been provided regarding the interpretation of the problem, clarifying that the results of the fractions do not need to be in set A. Participants are exploring the generation of fractions and the conditions for inclusion in the respective sets.

Contextual Notes

Participants express uncertainty about the requirements of the problem, particularly regarding the need for results to be members of set A and the distinction between real numbers and integers.

Flook
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Homework Statement



Hi, I need help with a couple of Set questions I just can't get my head around.

The question starts with:

Let

A = (-1, -2, 1, 2, 3, 5)

List the members of the following sets:

i) (x [itex]\in[/itex] R: x = m/n for m, n [itex]\in[/itex] A)

ii) (x [itex]\in[/itex] Z: x = m/n for m, n [itex]\in[/itex] A)


Homework Equations





The Attempt at a Solution



R will be real numbers and Z will be integers? I just can't seem to understand the rest. Any help ould be greatly appreciated.

Thanks
 
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Flook said:

Homework Statement



Hi, I need help with a couple of Set questions I just can't get my head around.

The question starts with:

Let

A = (-1, -2, 1, 2, 3, 5)

List the members of the following sets:

i) (x [itex]\in[/itex] R: x = m/n for m, n [itex]\in[/itex] A)

ii) (x [itex]\in[/itex] Z: x = m/n for m, n [itex]\in[/itex] A)

The Attempt at a Solution



R will be real numbers and Z will be integers? I just can't seem to understand the rest. Any help would be greatly appreciated.

Thanks

For i:

Generate all of the fractions you can make from the elements of set A, but using one element for the numerator and one element (possibly the same element) the denominator.

For ii:

Do the same as for part i, except you keep only the fractions which simplify to be integers.
 
Thanks for your response!

So for i)

I use A = (-1, -2, 1, 2, 3, 5) and make fractions, every possible combination?

-1/-2 = a half 1/2, but I wouldn't list that as it is not in set A?

so next would be -1/1 which is -1, so that is in set A?

I still don't get it I think.
 
No, the results don't have to be in A! You need to form all possible fractions- as the problem said, m/n with both m and n from A. All of those will be in (i) but only those that reduce to integers will be in (ii).
 
Ahh ok thank you HallsofIvy!
 

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