Help with Stoich limiting reactant Lab

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The discussion revolves around a lab involving the reaction between BaCl2·2H2O and Na2SO4, where the participant seeks assistance in calculating the mass of the excess reactant, BaCl2. They have provided data on the moles and masses of the products and reactants, indicating that BaSO4 is the precipitate formed and that sulfate (SO4) is the limiting reactant. There is confusion regarding the initial amounts of the reactants and the relevance of the provided numbers. Participants emphasize the need for clearer context and details about the lab to assist effectively. The thread highlights the importance of understanding stoichiometry in determining limiting and excess reactants in chemical reactions.
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Help with Stoich limiting reactant Lab urgent!

1. I need to find the mass of the excess reactant. This was a lab i did. so its BaCl2.2H20 + Na2So4 --> BaSO4 + 2NaCL. The data i have calculated thus far is.

moles of BaSO4=0.0019 mol
moles of BaCl2=0.0019 mol
moles of Na2SO4=0.0019 mol

mass of BaSo4=.4524g
mass of BaCl2=.4641g
mass of Na2So4= .2698g

Mass of entire salt mixture=1.0038g

The limiting reactant is SO4 and excess is Ba.

BaSo4 is the precipitate.

How do i get the excess reactant!
 
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What are the initial amounts of the reactants? I don't quite understand what the numbers you gave are for.
 


As Bohrok wrote - you have failed to explain what the question is. What the lab, what you did, what are these numbers. We are not mind readers.

It may came usefull, but we are not.

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methods
 
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