B Help With the Twin Paradox: Why Does Time Dilation Apply?

[pixel]

To remove the question of acceleration, you can use the version with triplets. Each is moving inertially throughout. The departing sibling synchronises his clock with stay-at-home as he passes home station and the third triplet who is already returning home sync's his clock as he passes the departing ship. The returning triplet's clock is then not sync'd with home station when he gets back.

If the third triplet syncs his clock with one that is already out of sync with the stay-at-home's clock, it seems evident that then those two clocks would be out of sync when they pass each other. Where is the paradox?

 

[GeorgeDishman]

Where is the paradox?

When you know the answer and look at spacetime the right way, it is sometimes hard to see why anyone would think there was a paradox at all. It is the same argument as the twins, since the departing and returning twins both see stay-at-home's clock slowed relative to their own, and they sync'd theirs as they passed, the total time registered by stay-at-home should be less than the final time shown on the returning triplet's clock, but since stay-at-home saw both their clocks slowed, he thinks it is their cumulative time that should be less.

 

[dragoo]

There is no acceleration parameter In the equations. The acceleration is no matter.
"this frame switch is the reason for the aging difference, not the acceleration per se"
https://en.wikipedia.org/wiki/Twin_paradox