Help with these two problems in complex analysis

Mathematicsss

Homework Statement


What is the argument of -4-3i, and -4+3i?

Homework Equations


tantheta=opposite/adjacent side
The principle of argument is that the argument lies between -pi and pi (not including -pi).

The Attempt at a Solution


arg(-4-3i) = -pi + arctan(3/4)
arg(-4+3i) = pi - arctan(3/4)

My teacher wrote on the answer sheet that the argument of -4-3i is just arctan(3/4).. am I incorrect in the above arguments?[/B]
 
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You are correct.
 
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Drawing a picture also will help you figure out an approximate angle, to see if you figured it correctly.
 
Mathematicsss said:

Homework Statement


What is the argument of -4-3i, and -4+3i?

Homework Equations


tantheta=opposite/adjacent side
The principle of argument is that the argument lies between -pi and pi (not including -pi).

The Attempt at a Solution


arg(-4-3i) = -pi + arctan(3/4)
arg(-4+3i) = pi - arctan(3/4)

My teacher wrote on the answer sheet that the argument of -4-3i is just arctan(3/4).. am I incorrect in the above arguments?[/B]
Your prof. may have been referring to the fact that angles in the Complex plane depend on the "frame of reference" for angles, as well as to the periodicity. If , e.g., the x-axis corresponds to 0 , then you will have a certain angle, if you set the y-axis to be the 0 -reference, you will have another angle, etc. This relates to what is called a branch of the associated function of logarithm.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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