Maximizing Kinetic Energy | Solving a Force Problem with F=12-2xN for a 2kg Body

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1.the only force acting on a 2kg body as it moves along the x-axis is given by F=(12-2x)N where x is in m. the velocity of the body at x=2m is 5.5i m/s. what is the maximum kinetic energy attained by the body?




2. KE= mv^2



3. My friend said the answer is 46J but I am not sure how he got it
 
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You will need to find the maximum of |v(x)|. You know F(x) and mass. What quantity related to the velocity do you therefore know?
 
help!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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