Help with understanding how to figure out the amount of heat to boil away water.

AI Thread Summary
To determine the heat required to boil away 2300 grams of water starting at 17 degrees Celsius, two calculations must be performed. First, the temperature difference to reach boiling point is 83 degrees Celsius, which is used in the formula Q = c m ΔT, where c is the specific heat of water. Next, the heat of vaporization is calculated using Qv = m Lv, with Lv being 540 calories per gram. The total heat needed is the sum of the heat required to raise the temperature to 100 degrees Celsius and the heat needed for vaporization. Understanding these calculations is essential for solving the problem accurately.
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1. The problem statement, all variables and given/know

2300 grams of water is heated. If this water starts at a temperature of 17 degrees Celsius, what amount of heat is needed to boil away all of this water? Note that the specific heat of water is 1 calorie per gram per degree Celsius, the Heat of vaporization of water is 540 calories per gram, and water boils at 100 degrees Celsius.

The Attempt at a Solution



I figured that this would be the best formule for me to use Q = c m ΔT, and Qv = m Lv .

Since water boils at 100 degrees celsius, I assumed that I should subtract 100-17 to get 83 degrees as the differnce in temperature.

Can I please get assistance with understanding this probelm.
 
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Actually, you are on the right track. Use your two formulas. The total heat is the sum of the two.
 
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