Help with velocity vs, time graph

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SUMMARY

The discussion focuses on creating a velocity vs. time graph for a scenario involving a car's movement. The graph consists of several segments: a horizontal line at zero velocity while waiting at a traffic light, a positive diagonal line representing acceleration to the speed limit, a horizontal line at constant speed, and a negative slope indicating deceleration until the car stops at a red light. The key takeaway is the representation of these phases through distinct linear segments on the graph.

PREREQUISITES
  • Understanding of basic graphing concepts
  • Familiarity with velocity and time as variables
  • Knowledge of linear equations and slopes
  • Ability to interpret graphical data
NEXT STEPS
  • Research how to plot linear equations on a graph
  • Learn about the relationship between acceleration and velocity
  • Explore graphical representations of motion in physics
  • Study the concepts of constant speed and deceleration
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Students studying physics, educators teaching motion concepts, and anyone interested in understanding graphical representations of velocity and time.

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Homework Statement


Draw a velocity vs. Time graph Please I REALLY need HELP!?
7. Sketch a velocity versus time graph of Tommy in his car for the following situation. [5]

• He is waiting at a traffic light.
• He accelerates up to the speed limit.
• Travels at the speed limit for a while.
• Decelerates when he sees a red light.
• Stops at the light for a while.


Homework Equations


There are no equations


The Attempt at a Solution



I don't know how to draw this!
I need help
please!
 
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Okay, so if he is waiting at a traffic light, his velocity should=0. Time is still passing, so its a straight line but it sits on top of the x-axis (y=0). When he accelerates, his velocity will raise over time, so that's a positive diagonal line. Now he is cruising at a constant velocity. That's a straight line at some positive value of y. When he decelerates, the line goes downwards (make a negative slope) and it will eventually hit zero, where it will just go along the x-axis again.
 

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