Hey, so I am just working on a second year Analytical Mechanics

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SUMMARY

The discussion centers on solving two problems related to damped oscillators in a second-year Analytical Mechanics assignment. The undamped frequency (f0) of a damped oscillator with a frequency (fd) of 100 Hz and an amplitude ratio of one half is calculated to be 100.6 Hz. Additionally, for an overdamped harmonic oscillator with initial conditions specified, the displacement at time t = (2γ)-1 is determined to be zero due to the initial displacement being zero.

PREREQUISITES
  • Understanding of damped oscillators and their properties
  • Familiarity with the logarithmic function and its application in physics
  • Knowledge of harmonic motion and its equations
  • Basic calculus for solving differential equations related to motion
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  • Study the derivation of the damped oscillator equations
  • Learn about the effects of damping on oscillatory motion
  • Explore the concept of overdamping and underdamping in harmonic oscillators
  • Investigate the use of logarithmic functions in physical applications
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Students in physics or engineering programs, particularly those focusing on mechanics and oscillatory systems, will benefit from this discussion.

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Hey, so I am just working on a second year Analytical Mechanics assignment, and right now dealing with oscillations. I have two questions I am stumped on and don't know if I have it right. It is probably basic, but just checking.

6. The frequency fd of a damped oscillator is 100 Hz, and the ratio of
the amplitudes of two successive maxima is one half. What is the
undamped frequency f0 of this oscillator?

e-\gammaTd = \frac{1}{2}
\gamma = \frac{1}{T<sub>d</sub>}ln 2
fd ln 2
\varpid = (\varpi02 - \gamma2)\frac{1}{2}
\varpi0 = (\varpid2 + \gamma2)\frac{1}{2}
fo = [fd2 + \frac{\gamma}{2\pi}2]\frac{1}{2}
= fd[1+(\frac{ln2}{2\pi})2]\frac{1}{2}
fo = 100.6Hz

Is this correct?

7. An overdamped harmonic oscillator with ω0 = γ/2 is kicked out of equi-
librium x(t = 0) = 0 with the initial velocity v0. Find the displacement
x of the oscillator at time t = (2γ)-1.

As with this one, I don't know where to begin. Anyone be able to give me a hand starting it?

Cheers
 
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.For question 7, the displacement x at time t = (2γ)-1 is given by x(t) = x0 e-γt cos(ωd t), where x0 is the initial displacement and ωd is the damped frequency. In this case, the initial displacement x0 is 0 and the damped frequency is ωd = γ/2. Therefore, the displacement at time t = (2γ)-1 is x(t = (2γ)-1) = 0 e-(γ/2)(2γ)-1 cos((γ/2)(2γ)-1) = 0.
 

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