How can I understand wave graph conversion better?

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Understanding wave graph conversion involves recognizing the relationship between snapshot and history graphs. The snapshot graph illustrates wave displacement at a specific position, while the history graph shows how the medium's displacement changes over time at that position. The change in wave speed from 1 m/s to 3 m/s complicates these conversions, as it affects the timing and width of the wave features. Practicing with visual aids, such as drawing waves on transparencies, can enhance comprehension of these concepts. Overall, connecting the snapshot and history graphs requires careful consideration of time and position adjustments.
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Homework Statement


Number 6:
unnamed.jpg
For this problem I'm changing the wave speed to 3.0 m/s instead of 1 m/s because that's what our teacher instructed us to do.

Homework Equations


None that I know of

The Attempt at a Solution


I'm having the hardest time making connections between the graphs and more specifically converting one graph to the other. I understand that the snapshot graph represents the displacement of the wave as a function of x and make the analogy of "the experience" a particle will go through. Also I know that the history graph shows what is happening to the medium at the specific point. But when it comes to graphs that are a bit more complex than easier x positions and different velocities I lose track of what's going on.

With this problem it says it is a history graph at x=2m with the wave moving at 3 m/s. Knowing this I would say that for the snapshot, the 2m will be affected immediately by the wave because of the placement of the leading edge on the history graph.
I also recognized from my teacher's solution that each second that's hashed on the graph is equivalent to the 3 meters which is understandable, but I really can't connect with what's going on overall. Any help would be greatly appreciated, thank you.Here's my teacher's solution:
16-6.jpg
 
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Hello Riceking, :welcome:

Well, you got most of it!
From the figure in the book you saw x=2 starts going up at t=0 and is back to 0 at t=4, so the whole snapshot "up from zero" width must be 12 m.
Similarly: x=2 is at its peak at t=1, so the rising flank of the wave is 3 m wide. With the 1 cm amplitude, that's enough to draw teacher's picture.
Change from 1 m/s to 3 m/s was probably introduced by teacher becasue 1 m/s is almost too easy (either that, or he doesn't want to see tiny drawings being handed in :smile:)

My advice: practice.
What worked very well for me: drawing waves on transparencies and move them sideways over a piece of paper with coordinate lines.
 
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BvU said:
Hello Riceking, :welcome:

Well, you got most of it!
From the figure in the book you saw x=2 starts going up at t=0 and is back to 0 at t=4, so the whole snapshot "up from zero" width must be 12 m.
Similarly: x=2 is at its peak at t=1, so the rising flank of the wave is 3 m wide. With the 1 cm amplitude, that's enough to draw teacher's picture.
Change from 1 m/s to 3 m/s was probably introduced by teacher becasue 1 m/s is almost too easy (either that, or he doesn't want to see tiny drawings being handed in :smile:)

My advice: practice.
What worked very well for me: drawing waves on transparencies and move them sideways over a piece of paper with coordinate lines.
Hi BvU thank you for replying. Your explanation makes much more sense than I could understand by myself. Now, after what you said, I infer we use the snapshot graph to dictate what happens to the history graph after moving the position of the snapshot graph back to t=0sec? And for looking at the history graph and drawing the snapshot (like in problem 7), we would move the graph vt = x amount?
 
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