Homework in Solid state material

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The problem involves calculating the electric field near x=500nm in silicon, where electron concentration varies linearly from 5x10^15 cm^-3 at the surface to 10^15 cm^-3 at 500nm depth. The vertical electron current density is constant at Jn=100 A/cm^2, and mobility is given as 1250 cm^2/Vs. The relevant equation for total electron current density combines drift and diffusion components, expressed as J_n = q D_n (dn/dx) + q μ_n E. With known values for Jn and the gradient of electron concentration (dn/dx), the electric field (E) can be calculated as the only unknown. Understanding these relationships is crucial for solving the problem effectively.
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Here is the problem:

The electron concentration in a region of silicon depends linearly on depth with concentration of 5x10^15 cm^-3 at surface (x=0) and 10^15 cm^-3 at depth of x=500nm. If the vertical electron current density in this region is constant at Jn=100 A/cm^2, calculate the electric field near x=500nm. assume that the mobility is constant at 1250cm^2/Vs.

If anyone can at least explain the meaning of each value written in the problem and the formula that can be used to solve this problem ..

Thank you...
 
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The equation that you need is for the total electron current density (drift plus diffusion).

J_n = q D_n \frac{dn}{dx} + q \mu_n E

q = 1.6E-19

D_n = (kT/q) u_n which is approx 0.026 u_n at room temperature.

Since you know J_n and dn/dx then E is the only unknown.
 
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