Hooke's Law vs. Conservation of Energy

AI Thread Summary
The discussion focuses on the application of Hooke's Law and the conservation of energy in solving two physics problems involving springs. For the first question, the correct approach is to use Hooke's Law to determine the compression of the springs under a static load. In the second question, conservation of energy is appropriate to find how far a ball falls before being stopped by the spring. Misapplying the methods leads to incorrect results, specifically a factor of two difference in both cases. Understanding the context of each problem is crucial for selecting the appropriate method.
keroberous
Messages
15
Reaction score
1
Homework Statement
I can never quite remember when solving problems with elastic materials whether I should be using Hooke's Law or conservation of energy. Below are two sample problems.
Relevant Equations
Hooke's Law: ##F=kx##
Elastic Potential Energy: ##E_e=\frac{1}{2}kx^2##
Gravitational Potential Energy: ##E_g=mgh##
Here are the two questions I want to compare:

1. A student of mass 62 kg stands on an upholstered chair containing springs, each of force constant 2.4 × 103 N/m. If the student is supported equally by six springs, what is the compression of each spring?

2. A 0.20-kg ball attached to a vertical spring of force constant 28 N/m is released from rest from the unstretched equilibrium position of the spring. Determine how far the ball falls, under negligible air resistance, before being brought to a momentary stop by the spring.

I can get the right answer for both questions, by using Hooke's law for number 1 and conservation of energy for question 2. My question is if I didn't know what the answers were, how would I choose the method? By using the incorrect method I'm off by a factor of two in both cases (bigger in 1 and smaller in 2).
 
Physics news on Phys.org
keroberous said:
Here are the two questions I want to compare:

1. A student of mass 62 kg stands on an upholstered chair containing springs, each of force constant 2.4 × 103 N/m. If the student is supported equally by six springs, what is the compression of each spring?

2. A 0.20-kg ball attached to a vertical spring of force constant 28 N/m is released from rest from the unstretched equilibrium position of the spring. Determine how far the ball falls, under negligible air resistance, before being brought to a momentary stop by the spring.

I can get the right answer for both questions, by using Hooke's law for number 1 and conservation of energy for question 2. My question is if I didn't know what the answers were, how would I choose the method? By using the incorrect method I'm off by a factor of two in both cases (bigger in 1 and smaller in 2).
In question 1, you are asked to determine the equilibrium position of the system (student plus springs). In question 2, you are asked how far the ball would fall before it reverses direction. This is not the same as the equilibrium position and would in fact be twice as far from the initial position as the equilibrium position.
Each method, used correctly, should give you the right answer to each question. If you were to post your solutions, we could comment on where you went wrong.
 
tnich said:
Each method, used correctly, should give you the right answer to each question.
But... in 1, it is a static arrangement. A conservation law is only directly useful when something has changed.
Conversely, in 2, it is not obvious how to find the force when the velocity is zero.
To apply energy in 1 or Hooke in 2 seems to require performing the conversion, i.e. integrating Hooke or differentiating energy.
 
Any reason you can't turn 1) into a dynamic situation and equate the PE lost by the man with the PE gained by the spring...

mgh=0.5kh^2

Solve for h.
 
CWatters said:
Any reason you can't turn 1) into a dynamic situation and equate the PE lost by the man with the PE gained by the spring...
Yes, there is a reason. That will give twice the correct answer, as @keroberous found and @tnich explained.
 
  • Like
Likes CWatters
Palm -> Face
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top