Horizontal Range Homework: 45° & 30° Angles

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The discussion revolves around calculating the horizontal range of a ball thrown at angles of 45° and 30° with the same initial speed. The initial step involves breaking down the initial speed into horizontal and vertical components using trigonometric functions. The horizontal speeds for the 30° and 45° angles are determined as u x cos 30° and u x cos 45°, respectively. Participants express confusion about how to proceed without a time variable and seek clarification on the meaning of "horizontal range." The conversation highlights the importance of understanding the relationship between the angles and the resulting horizontal distances traveled.
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Homework Statement


A ball is thrown at angles 45° and 30° above the horizontal with the same initial speed. What multiple of the horizontal range at angle 30° is that at angle 45°?

Homework Equations


Trigonometry formula

The Attempt at a Solution


I think that first step is to divide the initial speed into horizontal component and vertical component.
Let the initial speed be u
Horizontal speed of 30° angles : u x cos 30° = 1 / 2 u
Horizontal speed of 45° angles : u x cos 45° = √2 / 2 u

After this I'm not sure what to do next.. Since the question didn't provide time, I can't use the kinetic equation formula.
Can anyone give me a hint about what should I do next?
 
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What do you think "horizontal range" means?
 
haruspex said:
What do you think "horizontal range" means?
Horizontal distance traveled..
Oh wait, I think I get something..
*edit
 
Yoruichi said:
Horizontal distance traveled..
Oh wait, I think I get something..
*edit
Horizontal distance traveled between two points having what relationship?
 
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