Horizontal Tangent Lines: Intersection of Cylinder and Plane

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Homework Help Overview

The discussion revolves around the intersection of a plane defined by the equation z = x + 2y and a cylinder described by x^2 + y^2 = 1. Participants are exploring the conditions for horizontal tangent lines along the curve formed by this intersection.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find a vector function representing the intersection and is struggling with identifying when the tangent vector is horizontal. Some participants question the understanding of when a vector is considered horizontal and discuss the implications of the vector components.

Discussion Status

Participants are actively engaging with the problem, clarifying definitions and exploring the conditions under which the tangent vector is horizontal. There is a recognition of the need to focus on specific components of the tangent vector, particularly the k component, to determine horizontal tangents.

Contextual Notes

There is some confusion regarding the interpretation of the tangent vector and its components, as well as the conditions for horizontal tangents. Participants are navigating through these assumptions without reaching a consensus.

Lothar
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Homework Statement



Consider the plane z = x + 2y and the cylinder x^2 + y^2 = 1

(a) Find a vector function r(t) describing their intersection.
(b) Find the points if any where the tangent to ~r is horizontal
(c) Find an equation for the tangent line to ~r at each of these points.

Homework Equations

The Attempt at a Solution



r(t) = cos(t)i+sin(t)j+(cos(t)+2sin(t))k
r'(t) = -sin(t)i + cos(t)j + (-sin(t)+2cos(t))k

These equations are correct, as I have plotted them in Maple 14 and the images appear correct. I'm having issues finding the horizontal tangent, and then finding the equations afterwards.
The horizontal tangent should be when r'(t) = 0 correct? I cannot find a value that makes this true. Maybe I'm making a mistake in my thinking?

Thank you for any help.
 
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Hi Lothar! :smile:

(try using the X2 icon just above the Reply box :wink:)
Lothar said:
The horizontal tangent should be when r'(t) = 0 correct?

No.

r' is a vector, it will be horizontal when … ? :wink:

(if r' was zero somewhere, you'd have a dodgy parameter! :rolleyes:)
 
tiny-tim said:
Hi Lothar! :smile:

(try using the X2 icon just above the Reply box :wink:)


No.

r' is a vector, it will be horizontal when … ? :wink:

(if r' was zero somewhere, you'd have a dodgy parameter! :rolleyes:)


Where r' is equal to pi or 2pi? Maybe? I'm kind of lost now.
 
Are we talking about the same thing? :confused:

r' is a vector, of the form (a,b,c) or ai + bj + ck

it can't be a number like π ror 2π …

when will that vector be horizontal?​
 
tiny-tim said:
Are we talking about the same thing? :confused:

r' is a vector, of the form (a,b,c) or ai + bj + ck

it can't be a number like π ror 2π …

when will that vector be horizontal?​

I'm not sure. That's why I asked.
When the j component is equal to zero?
 
Lothar said:
When the j component is equal to zero?

Nearly :rolleyes: … the k component! :wink:

(isn't that obvious … "horizontal" means moving only in the x,y plane, so no z ?)
 
Well I'm stupid. Still though, I don't see a point on the unit circle where 2cost - sint is equal to zero.
 
tant = 2 :smile:
 

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