- #1
Happiness
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I think the answer is incomplete, because proving that ##\psi(x)## isn't stationary doesn't prove that the particle isn't localised, it doesn't prove that ##\psi(x)\neq0## at ##0<x<\frac{a}{2}## at some later time. ##\psi(x)## could always be changing on the left side of the box (say from a horizontal flat line to sinusoidal and back) while always be ##0## on the right side of the box. So we have to prove that this is not possible (that is, the left-side ##\psi(x)## changes while the right-side ##\psi(x)## is always ##0##). Right?