How Accurate Are My Calculations on Alpha Particle Scattering and Energy?

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Hayool
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Hi,
upload_2016-3-26_17-17-34.png

I calculated the scattered angle & the kinematic factors for both Al & Au to be

upload_2016-3-26_17-32-48.png

Is what I did right?
Also
upload_2016-3-26_17-36-10.png

E (Alpha) = stopping power x depth
= 250 x 0.5 = 125 keV
As for the maximum & the minimum scattered energy i didn't know how?
 
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Any feedback would be appreciated, I'm really struggling.
 
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The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
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