How can a particle experiencing a force be solved using work and energy?

  • Thread starter Thread starter tangibleLime
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
To solve for the velocity of a particle experiencing a force, the work-energy theorem can be applied. The work done on the particle can be calculated using the integral of force over distance. This approach allows for determining the change in kinetic energy, which can then be used to find the final velocity. The initial conditions, including mass and initial velocity, are crucial for setting up the equations. Ultimately, using these principles leads to the solution of 6.8 m/s for the particle's final velocity.
tangibleLime
Messages
71
Reaction score
0

Homework Statement


A 600 g particle moving along the x-axis experiences the force shown in the figure . The particle's velocity is 2.0 m/s at x = 0\:{\rm{ m}}.

11.EX15.jpg


Homework Equations


The Attempt at a Solution


To be completely honest, I don't have a clue on how to even start this problem. I tried to use the 1D kinematic equations, but that didn't result in anything useful because I don't know the acceleration. I tried to find the acceleration with F=ma, but that still didn't make much sense. If I could get a nudge in the right direction, that would be awesome.

I know the answer is 6.8 m/s, but I do not know how to go about solving for that.
 
Physics news on Phys.org
Hi tangibleLime! :smile:

Use work done = ∫ (force).(distance), and the work-energy theorem. :wink:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top