How can a pi_0 meson decay into 2 photons?

AI Thread Summary
The discussion centers on the decay of a pi_0 meson into two photons, represented by the equation π_0 → γ + γ. The key issue raised is the conservation of spin, as the pi meson has a spin of 0 while each photon has a spin of +1. This leads to a total spin of +2 for the two photons, which seems to violate conservation laws. Participants note that while momentum, energy, charge, and baryon number are conserved, the spin conservation appears problematic. The conversation emphasizes the need to clarify how spin conservation works in particle decays involving photons.
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Homework Statement


Earlier my teacher put this equation on the board,
π_0 --> γ+γ
It appears to work until you consider spin.

Homework Equations


a quick google search reveals that the spin of a photon is +1 and the spin of a pi meson is 0

The Attempt at a Solution


This appears to work for momentum, energy, charge, baryon number...
But π_0 has no spin and γ has a spin of +1.
So in essence the atomic spin starts at 0 and finishes at +2.
What am I missing?
 
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Two particles with spin 1 don't have to add to spin 2.
 
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