How Can Engineers Design a Temperature-Independent Resistor?

AI Thread Summary
An engineer is tasked with designing a temperature-independent resistor using carbon and Nichrome cylinders, aiming for a total resistance of 15.0 Ω at 20°C. The problem involves determining the lengths of each segment while ignoring thermal expansion and assuming both materials are at the same temperature. The resistivity values for carbon and Nichrome are provided, with carbon having a positive temperature coefficient and Nichrome a negative one. The discussion highlights the need to set up equations based on the resistivity and resistance formulas, but participants express confusion over how to solve for two unknown lengths with only one equation. Clarification is sought on the relevance of the temperature independence to the overall design.
ktobrien
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Homework Statement



An engineer needs a resistor with zero overall temperature coefficient of resistance at 20°C. She designs a pair of circular cylinders, one of carbon and one of Nichrome.

The device must have an overall resistance of R1 + R2 = 15.0 Ω independent of temperature and a uniform radius of r = 1.40 mm. Determine the lengths l1 and l2 of the carbon and Nichrome segments respectively. You may ignore thermal expansion of the cylinders and assume both are always at the same temperature.

Homework Equations


R1+R2=15
alpha1+alpha2=0
R=pl/A
pcarbon = 3.5e-5
pnichrome = 1.5e-6



The Attempt at a Solution


I don't really know where to begin. The problem states that the 15ohms is independent of temperature. I know what that means but does it have any relevance to the problem? Any help getting started would be appreciated. Thanks
 
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ktobrien said:

Homework Statement



An engineer needs a resistor with zero overall temperature coefficient of resistance at 20°C. She designs a pair of circular cylinders, one of carbon and one of Nichrome.

The device must have an overall resistance of R1 + R2 = 15.0 Ω independent of temperature and a uniform radius of r = 1.40 mm. Determine the lengths l1 and l2 of the carbon and Nichrome segments respectively. You may ignore thermal expansion of the cylinders and assume both are always at the same temperature.

Homework Equations


R1+R2=15
alpha1+alpha2=0
R=pl/A
pcarbon = 3.5e-5
pnichrome = 1.5e-6



The Attempt at a Solution


I don't really know where to begin. The problem states that the 15ohms is independent of temperature. I know what that means but does it have any relevance to the problem? Any help getting started would be appreciated. Thanks

One of those materials would have to have a negative temperature coefficient of resistance. Double check the rho numbers -- is one negative?
 
Rho is the resistivity. Alpha is the temperature coefficient. Both values of resistivity are positive as written. Carbons temperature coefficient is positive and nichromes is negative.
 
ktobrien said:
Rho is the resistivity. Alpha is the temperature coefficient. Both values of resistivity are positive as written. Carbons temperature coefficient is positive and nichromes is negative.

Ah, thanks for the catch. My bad.
 
Could still use some help. Thanks.
 
The two alpha's don't need to add up to zero; R1 and R2 just need to sum to 15--not 15+0.2T or anything, just 15. All the other relevant equations are correct. Why not plug them all into R1+R2=15 and see what you get?
 
Plugging into the two formulas I got.

3.5e-5(l1) + 1.5e-6(l2) = 9.2363e-5

but this gives me 1 equation and 2 unknowns
 
Can someone please help me out?
 
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