How can I calculate the max velocity for a car climbing a 15-degree hill?

  • Thread starter Thread starter zacazac33
  • Start date Start date
  • Tags Tags
    Velocity
AI Thread Summary
To calculate the maximum velocity of a 3000-lb car climbing a 15-degree hill with an 80-hp engine, one must consider the power output in relation to gravitational potential energy. The engine's power translates to approximately 60 kJ/s, which is the rate at which energy is converted to maintain motion. The key is to determine the rate of elevation gain that this power can support. Understanding the relationship between energy per unit time and the change in elevation will help in solving the problem. This approach will yield the maximum velocity for the car on the incline.
zacazac33
Messages
1
Reaction score
0
velocity problem! NEED HALP ASAP!

hellloooo physics friends ok here's the issue:

A 3000-lb. car has an engine which can deliver 80-hp. to the rear wheels. What is the max velocity at which the car can climb a 15-degree hill?

We were told this must be answered tomorrow for part of our final, and I absolutely have no idea what to do. Help would be greatly appreciated!

-zac
 
Physics news on Phys.org
Are you sure it is velocity and not acceleration?
 
The velocity up the hill specifies a certain change in evelation per unit time.

Change in gravitational potential energy can be defined in terms of change in evelation. Since you know how fast the elevation is changing, you know how fast the gravitational potential energy is changing.

Energy per unit time is power.

To keep the car moving at a steady velocity up the hill, the engine is converting energy in the fuel into increasing gravitational potential energy at a rate of 80 hp, or about 60 kJ/s: http://www.google.com/search?hl=en&q=80+hp+in+joules/second&btnG=Google+Search

All you have to do is figure out what rate of elevation gain would require 60kJ/s to maintain.

- Warren
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top