How can I calculate the number of photons with this data?

AI Thread Summary
The discussion revolves around calculating the number of photons emitted by a radio station with a frequency of 100 MHz and a power output of 6.63 kW. The initial confusion stems from the incorrect rearrangement of the formula for power, leading to an erroneous photon count. The correct formula, P = (N * h * f) / t, allows for the calculation of the number of photons emitted per second. By using the correct rearrangement, participants confirm that the number of photons can be accurately determined, aligning with the teacher's result. Ultimately, the key takeaway is the importance of correctly manipulating equations in photon calculations.
HazyMan
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The problem says: A radio station emits electromagnetic wave with a frequency of 100MHz (102*106 Hz).
a)What's the energy of this radiation's/glow's photon? (Solved, i found 6,63*10-26 J)
b)Compare your calculation with the energy of another visible radiation/glow, with a wavelength of 600nm (6*102*10-9 m). (Solved as well, found 3,315*10-19 J)
c) and the part that BUGS me, FIND THE NUMBER OF PROTONS EMITTED IN 1 SECOND, IF THE RADIATED/GLOWED POWER IS 6,63kW (6,63*103 W)

The problem with this question is that i came up with this formula: N=t(h*f/P) where N is the number of the photons and P the power. Using this i came up with 10-37 which confuses me, because my teacher had used a different way and found 1029. He took the E=pt formula and turned it into E=N*Ep (Ep is the photon energy that was calculated in question a) and then he created a N=E/Ep [or N=(P*t/Ep)] where he got HIS result from. Can anyone help me? I'm confused.

OTHER EQUATIONS USED: Ep=hf, f2=Co/λο (where f2 is the freq. of the other radiation/glow from question b), Ep2=hf2 (where Ep2 is the photon energy of the other radiation/glow from question b).
 
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HazyMan said:
The problem with this question is that i came up with this formula: N=t(h*f/P) where N is the number of the photons and P the power.
Does this formula make sense? The higher the power, the fewer the number of photons you get.
 
DrClaude said:
Does this formula make sense? The higher the power, the fewer the number of photons you get.
Well I'm not sure. From a video that I've seen someone mentioned this formula: P=(N*h*f/t) so by replacing the symbols with numbers, i concluded to the N=t(h*f/P) formula.
 
HazyMan said:
Well I'm not sure. From a video that I've seen someone mentioned this formula: P=(N*h*f/t) so by replacing the symbols with numbers, i concluded to the N=t(h*f/P) formula.
The formula is correct: P=(N*h*f/t). hf is the energy of 1 photon, to multiplying by N gives you the total energy, dividing by time gives you the power.

The problem is that you have not rearranged the terms correctly.
 
DrClaude said:
The formula is correct: P=(N*h*f/t). hf is the energy of 1 photon, to multiplying by N gives you the total energy, dividing by time gives you the power.

The problem is that you have not rearranged the terms correctly.
Oh my, well i should try again.
 
DrClaude said:
The formula is correct: P=(N*h*f/t). hf is the energy of 1 photon, to multiplying by N gives you the total energy, dividing by time gives you the power.

The problem is that you have not rearranged the terms correctly.

Is P=(N*h*f/t) equal to P=N(h*f/t) ?
 
Alright, i managed to get the same result my teacher did by using a different method. I used the formula: N=P/(hf/t)

In LaTeX: N=P/(hf/t)
 
HazyMan said:
Alright, i managed to get the same result my teacher did by using a different method. I used the formula: N=P/(hf/t)

In LaTeX: N=P/(hf/t)
That's the correct equation.
 
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