How can I find the coefficient of friction for an object on an inclined plane?

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To find the coefficient of friction for an object on an inclined plane, use the angle at which the object begins to slide, which is 20 degrees in this case. The equation mgsin(θ) - Ffmax = 0 can be applied, where θ is the angle of inclination. The frictional force can be calculated using the formula Ff = Us * N, where N is the normal force. It is clarified that using 20 degrees is appropriate, as the object starts to slide at this angle. The discussion emphasizes understanding the relationship between force, friction, and motion on an incline.
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Homework Statement


So I have and inclined plane at 1 degrees, and on top of it, there is an object 361grams. I gradually increase the angle of the inclined plane, and just at 20 degrees, the object starts to slide down. How do I find out the coefficient of friction?



Any help would be appreciated.

Thanks



Homework Equations





The Attempt at a Solution



I only know that just before it is about to slide down, mgsin20-Ffmax=0
so do i use 19.99999 degrees to solve this equation? So i used mgsin19.999=Usmgcos19.9999

and got 1.299999N but I think its wrong.
 
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Not necessarily when resultant force is 0, the object does not move.

For example, take the case when you are pushing an object with a force F, and there is a friction f equal to the force you are applying, the object moves with constant speed v, but there is no acceleration. a = 0.

Fresultant= m*a, so when Fresultant= 0 then you don't have acceleration.

So basically, you don't have to make it 19.9999999, it is 20 degrees.

I have attached a jpeg with the sketched problem. Have a look at it. Good luck
 
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