How can I rearrange the equation x = y(1-z)/π√z to solve for z?

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To rearrange the equation x = y(1-z)/π√z to solve for z, it can be transformed into a quadratic equation. By substituting u = √z, the equation becomes yu² + πxu + y = 0. This quadratic can be solved using the quadratic formula, and then squaring u will yield the value of z. The discussion highlights the importance of correctly manipulating the equation to arrive at the solution. Ultimately, the user successfully solved for z after converting the equation into a quadratic form.
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Hi,

I have recently returned to education after 15 years out and I am finding that it is my basic maths that causes me the most problems. I have the following equation

x = y (1-z)/ \pi \sqrt{}z

so you know, that's pi multiplied by root z.

and I can't solve for z, can someone rearrange this equation for me.

thanks
 
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Do you mean
x= \ffrac{y(1-z)}{\pi\sqrt{z}}[/itex]?<br /> That would be the same as \pi x\sqrt{z}= y- yz or yz+ \pi x\sqrt{z}- y= 0.&amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; Let u= \sqrt{z} so that u^2= z. Then the equation becomes yu^2+ \pi xu+ y= 0, a quadratic equation for u. That can be solved using the quadratic formula and then square u to find z.
 
To me that kind of looked like:

x = \frac{y(1-z)}{\sqrt[\pi]{z}}

But it could be anything.
 
sorry I will try again, the equation should be

<br /> x = \frac{y(1-z)}{\pi\sqrt{z}} <br />

then solve for z

thanks
 
Last edited:
substitute z&#039;=\sqrt{z} and you get a quadratic eq.. Then multiply both sides by \pi z&#039;
 
Thanks guys, I got the answer i was looking for after I made it into a quadratic.

Thanks for your help
 
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