How Can I Simplify and Solve the Einstein Summation Convention Problem?

Athenian
Messages
143
Reaction score
33
Homework Statement
Solve ##a_i \, b_j \, c_k \, \epsilon_{ij \ell} \, \epsilon_{3k \ell}##
Relevant Equations
See Below ##\longrightarrow##
Attempted Solution:
$$a_i \, b_j \, c_k \, \epsilon_{ij \ell} \, \epsilon_{3k \ell}$$
$$a_i\, b_j\, c_k\, (\delta_{i3} \, \delta_{jk} - \, \delta_{ik}\, \delta_{j3})$$

Beyond this, though, I am quite lost. I know I am very close to the answer, but seeing this many terms can become fairly confusing for me. Is there a way or method to better (and simply) digest the above problem and solve it?

Any help would be greatly appreciated. Thank you!
 
Physics news on Phys.org
Athenian said:
Homework Statement:: Solve ##a_i \, b_j \, c_k \, \epsilon_{ij \ell} \, \epsilon_{3k \ell}##
Relevant Equations:: See Below ##\longrightarrow##

Attempted Solution:
$$a_i \, b_j \, c_k \, \epsilon_{ij \ell} \, \epsilon_{3k \ell}$$
$$a_i\, b_j\, c_k\, (\delta_{i3} \, \delta_{jk} - \, \delta_{ik}\, \delta_{j3})$$

Beyond this, though, I am quite lost. I know I am very close to the answer, but seeing this many terms can become fairly confusing for me. Is there a way or method to better (and simply) digest the above problem and solve it?

Any help would be greatly appreciated. Thank you!
That's the correct first step. Now, each Kronecker delta can be used to get rid of one of the indices that appears in it. For example, what happens if you sum over the index "i"?
 
  • Like
Likes JD_PM and Athenian
@nrqed, thank you for the helpful hint and guidance! I was finally able to figure it out as seen below:

Continuing where I left off:
$$a_i \, b_j \, c_k \, \delta_{i3} \, \delta_{jk} - a_i \, b_j \, c_k \, \delta_{ik} \, \delta_{j3}$$
$$\Rightarrow a_3 \, b_k \, c_k - a_i \, b_c \, c_i$$
$$\Rightarrow a_3 (b \cdot c) - b_3 (c \cdot a)$$

Thank you for all your help!
 
  • Like
Likes nrqed
Athenian said:
@nrqed, thank you for the helpful hint and guidance! I was finally able to figure it out as seen below:

Continuing where I left off:
$$a_i \, b_j \, c_k \, \delta_{i3} \, \delta_{jk} - a_i \, b_j \, c_k \, \delta_{ik} \, \delta_{j3}$$
$$\Rightarrow a_3 \, b_k \, c_k - a_i \, b_c \, c_i$$
$$\Rightarrow a_3 (b \cdot c) - b_3 (c \cdot a)$$

Thank you for all your help!
Good job!
 
  • Like
Likes Athenian
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top