How can I simplify sqrt( 4t^2 + 4 + ( 1/t ) ) to (2t^2 + 1)/t?

Peter5897
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Couldn’t decide if I should put this in the calculus or general math forums but...

I’m studying for a final that’s coming up this Wednesday and I’ve been looking at some past quizzes with the steps to finding the solutions that my instructor has posted online. Given the problem:

1. Compute the length of the curve~r(t) = (t^2, 2t, ln(t)), from t = 1 to t = e.

I understand that I need to take the integral from 1 to e of the sqrt( (dx/dt)^2 + (dy/dt)^2 + (dz/dt)^2) but unfortunately I’m having trouble taking the sqrt.

I get down to… *EDITED*sqrt( 4t^2 + 4 + ( 1/t^2 ) ) and I get stuck even with the answer and the steps in front of me. In the next step the problem gets simplified so as to have everything over a t^2 and then the sqrt is done and I’m left with the integral from 1 to e of (2t^2 + 1)/t.

I’m hoping someone could explain to me how sqrt( 4t^2 + 4 + ( 1/t ) ) becomes (2t^2 + 1)/t.

I’m ashamed I don’t know this but I don’t want to get stuck trying to do algebra on a calculus final.

Thanks in advance.
 
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Well,

\sqrt{4t^2+4+\frac{1}{t}}

doesn't reduce to

\frac{2t^2 +1}{t}.

So it's good that you can't figure that out!

Your error was forgetting to square \frac{dz}{dt}.
 
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Ack, I wish that was my problem but I actually just mistyped it up there.

I still don't see how sqrt( 4t^2 + 4 + ( 1/t^2 ) ) gets reduced to (2t^2 + 1)/t and I'm sure it's some simple step that I'm missing.

Sorry...
 
\sqrt{4t^2 + 4 + \frac{1}{t^2}} = \sqrt{\frac{4t^4 + 4t^2 + 1}{t^2}} = \frac{1}{t}\sqrt{4t^4+4t^2+1} = \frac{1}{t}\sqrt{(2t^2+1)^2} = \frac{2t^2+1}{t} :smile:
(for t > 0)
 
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Thank you, I always got stuck at step 2. In fact at one point I was sitting there with sqrt( ( 2t^2 + 1)^2 / t^2 ) ) and was baffled...

Thanks again, the world makes sense now.
 
Peter5897 said:
In fact at one point I was sitting there with sqrt( ( 2t^2 + 1)^2 / t^2 ) ) and was baffled...

:smile:
happens to everyone sometimes.

Peter5897 said:
Thanks again, the world makes sense now.

Good :smile:. Don't be afraid to come back with more questions!
 
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