How can I simplify this expression using index laws?

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Homework Help Overview

The problem involves simplifying the expression \(\frac{x^{-2} - y^{-2}}{x^{-1} - y^{-1}}\) while expressing the result with positive indices. The original poster indicates difficulty recalling index laws and expresses uncertainty about how to manipulate the expression correctly.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various methods for simplifying the expression, including converting negative indices to fractions and recognizing the difference of squares. Some participants question the validity of canceling terms and the application of index laws.

Discussion Status

There are multiple lines of reasoning being explored, with some participants suggesting different approaches to simplify the expression. Guidance has been offered regarding the recognition of common factors and the use of algebraic identities.

Contextual Notes

Participants note that the problem may not solely rely on index laws, indicating a potential misunderstanding of the problem's requirements. There is also a mention of homework rules regarding posting new problems.

miniradman
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Homework Statement


Simplify; expressing with positive indices.

[tex]\frac{x^{-2} - y^{-2}}{x^{-1} - y^{-1}}[/tex]

The Attempt at a Solution


Hello, I'm doing first year uni math and over the holidays, I forgotten my index laws and as a result I'm stuck on this question :rolleyes:

I know that the answer is:

[tex]\frac{x+y}{xy}[/tex]

However I cannot figure out which laws relate to the equation.

I don't think I can just cancel the x's and y's here, because of that takeaway sign. Also I cannot bring the denominator up because I don't know what the rule is for that.

Can someone please give me a hint towards the right direction?
 
Last edited by a moderator:
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miniradman said:

Homework Statement


Simplify; expressing with positive indices.

[tex]\frac{x^{-2} - y^{-2}}{x^{-1} - y^{-1}}[/tex]

The Attempt at a Solution


Hello, I'm doing first year uni math and over the holidays, I forgotten my index laws and as a result I'm stuck on this question :rolleyes:

I know that the answer is:

[tex]\frac{x+y}{xy}[/tex]

However I cannot figure out which laws relate to the equation.

I don't think I can just cancel the x's and y's here, because of that takeaway sign. Also I cannot bring the denominator up because I don't know what the rule is for that.

Can someone please give me a hint towards the right direction?

This problem actually doesn't have too much to do with the index laws. Begin by removing the indices by converting them into fraction, then simplify from there.

OR if you prefer,
Notice that [itex]x^{-2}-y^{-2}=(x^{-1})^2-(y^{-1})^2[/itex] which is a difference of 2 squares.
 
Last edited by a moderator:
Hello Mentallic, expanding the brackets gives me

[tex]\frac{(\frac{1}{x}+\frac{1}{y})(\frac{1}{x}-\frac{1}{y})}{\frac{1}{x}-\frac{1}{y}}[/tex]

How do I proceed from here? because I cannot see a way which will give me positive index values. Do I take both brackets in the numerators down to the denominator?

Mod note: You don't need to use the HTML SIZE tags to make your LaTeX bigger - just use tex tags instead of itex tags.[/color]
 
Last edited by a moderator:
Notice the common factor in the numerator and denominator?
 
Ahhh... I see it now.

Then I just multiply the remaining bracket by [itex]\frac{xy}{xy}[/itex] to finish off the question.

Thanks a lot Mentallic :)
 
My first thought was to multiply both numerator and denominator by [itex]x^2y^2[/itex]:
[tex]\frac{x^{-2}- y^{-2}}{x^{-1}- y^{-1}}= \frac{y^2- x^2}{xy^2- x^2y}[/tex]
[tex]= \frac{(x+ y)(x- y)}{xy(y- x)}[/tex]
 
That works too! :)

If I have another problem I am stuck on relating to index laws, may I post it on this thread, or do I have to open a new topic?
 
miniradman said:
That works too! :)

If I have another problem I am stuck on relating to index laws, may I post it on this thread, or do I have to open a new topic?
For a new problem, please start a new thread.
 

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