How Can I Solve 2^n = 150 / 0.5 for n Using Logarithms?

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To solve the equation 2^n = 150 / 0.5, first simplify the right side to get 2^n = 300. Using logarithms, you can express n as n = log2(300). The values of n can be estimated since 2^8 = 256 and 2^9 = 512, indicating that n is between 8 and 9. Understanding logarithms is essential for solving exponential equations like this one.
n108
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I needed help with this equation:
2^n = 150 / 0.5
I don't know how to solve for the unknown "n" (which in this problem is the number of half lives) if its the exponent of something. what do I do?
 
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Please do not post your questions here. They should be posted in the appropriate forums.

With respect to your question, take logs, that's all there is to it...
 
Thread moved to Homework Help, Pre-Calculus Math.

n108, do you see a way that you could use logarithms to help you solve that equation for n?
 
First thing for you to do is divide 150/.5= 300. Now you have 2n= 300. Now 28= 256 and 29= 512. Since 300 is between 256 and 512, n is between 8 and 9. Do you know about logarithms?
 

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