How can I solve for x in a transcendental equation?

  • Thread starter Thread starter Nusc
  • Start date Start date
Nusc
Messages
752
Reaction score
2

Homework Statement


Suppose I have the following expression:

k + sin(g-x)= x-c

where k, g, c are constants, how can I solve for x?

Homework Equations

The Attempt at a Solution


I don't think trig identities will help me in this case. If I square both sides then I get more junk.
 
Physics news on Phys.org
Draw the graph for sin(a-x) then draw the graph for b+sin(a-x)
Draw the graph for x-c
find points of intersection.
 
This is a transcendental equation, and is pretty tough to solve. First, rewrite it as ##\sin (g-x)= x+c_1## where ##c_1 := -c-k##. What kind of solution are you looking for? If graphical works (sometimes it's all that's required) make a plot and let ##f=\sin (g-x)## and ##g=x+c_1## and look for their intersection.

If this isn't what you're looking for you can try using Newton's method (I assume you may use calculus).
 
  • Like
Likes AdityaDev
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top