How Can Stirling's Formula Be Proven Using Calculus?

  • Thread starter Thread starter Elysian
  • Start date Start date
  • Tags Tags
    Formula
Elysian
Messages
33
Reaction score
0

Homework Statement



Prove that

lim_{n \rightarrow ∞} \frac{n! e^{n}}{n^{n+\frac{1}{2}}} = \sqrt{2π}

Homework Equations

The Attempt at a Solution


Alright so for this problem I noticed it looked kind of similar to the integral formula for a normal distribution from statistics with the 1/\sqrt{2π} in it, but I'm not really sure what to do. I imagine there's a sine and cosine somewhere in there but I'm not exactly sure how to bring it in, maybe via taylor polynomials through the terms given?

I've yet no definitive solution but I've got some basic outlines of ideas.. I'm right now in Calc 2 so i expect there to be series and sequences involved..
 
Physics news on Phys.org
Elysian said:

Homework Statement



Prove that

lim_{n \rightarrow ∞} \frac{n! e^{n}}{n^{n+\frac{1}{2}}} = \sqrt{2π}


Homework Equations




The Attempt at a Solution


Alright so for this problem I noticed it looked kind of similar to the integral formula for a normal distribution from statistics with the 1/\sqrt{2π} in it, but I'm not really sure what to do. I imagine there's a sine and cosine somewhere in there but I'm not exactly sure how to bring it in, maybe via taylor polynomials through the terms given?

I've yet no definitive solution but I've got some basic outlines of ideas.. I'm right now in Calc 2 so i expect there to be series and sequences involved..

Google is your friend.

RGV
 
Ray Vickson said:
Google is your friend.

RGV

Thanks but it doesn't really give me a decent method I can follow. Some of the methods make little sense to me
 
My first question is this, how rigourous do you want this to be? It can be very long and in depth proof or it can be a paragraph. If this is homework, I'm assuming the short proof without a lot of detail is preferred?

First, step, is look at the log(n!). Transform this into something useful and think about if it's a decreasing and increasing function. From there determine an inequality that is always true.
 
Last edited:
Elysian said:
Thanks but it doesn't really give me a decent method I can follow. Some of the methods make little sense to me

There are several web pages that present several approaches. If you don't like one of them , go to another. All of them require some calculus and some hard work.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top