How Can Surface Charge Density Equal bcos(θ)?

AI Thread Summary
The discussion centers on the relationship between surface charge density and the variables involved in a hemispherical surface. The surface charge density is defined as ρ_s(z) = z, which is interpreted as having units of charge per area (C/m²), rather than charge per volume (C/m³). Clarification is provided that the variable z is a coordinate without units, and the confusion arises from the interpretation of the radius b and its relation to the charge density. The suggestion is made to express the charge density in terms of a constant ρ_0, leading to a clearer understanding of the units involved. This resolution highlights the importance of correctly interpreting the dimensions in electrostatics.
jeff1evesque
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Homework Statement



A surface is defined by a hemisphere of radius b, centered on the x-y plane. The surface charged density is given by \rho_s(z) = z (\frac{Coul}{m^3}).

Homework Equations


\rho_s(z) = z = Rcos(\theta) = bcos(\theta) (\frac{Coul}{m^3}).


3. Question
My question is how can the surface charge density equal to Rcos(\theta) = bcos(\theta)? That is a measure of the distance from the origin to the surface [element], and thus only [to my knowledge] have units of radius b, or meters \neq (\frac{Coul}{m^3}).

Thanks,


JL
 
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z has no units, it's just a coordinate in the coordinate system, and what they are saying is that the charge density at points with coordinates (x,y,z) is equal to z C/m2. (You wrote C/m3 which I'm assuming is a typo since we're talking about a surface, not a 3D region.)
 
dx said:
z has no units, it's just a coordinate in the coordinate system, and what they are saying is that the charge density at points with coordinates (x,y,z) is equal to z C/m2. (You wrote C/m3 which I'm assuming is a typo since we're talking about a surface, not a 3D region.)

Sorry about the typo. But what about the variable b which has units of meters? How does that fit into the interpretation of surface charges?

Thank you.
 
dx said:
... the charge density at points with coordinates (x,y,z) is equal to z C/m2. (You wrote C/m3 which I'm assuming is a typo since we're talking about a surface, not a 3D region.)
No typo. One unit of length in z cancels one unit of length in the denom. of C/m^3.

jeff1evesque said:
\rho_s(z) = z = Rcos(\theta) = bcos(\theta) (\frac{Coul}{m^3}).
This is misleading (i.e. wrong). The first inequality should be confusing. I would suggest:
<br /> \rho_s(z)=\rho_0z\rightarrow{}\rho_0Rcos(\theta)=bcos(\theta) (C/m^3)<br />
where \rho_0 is some unknown constant that has units of charge-per-volume and R and b have units of length.
Or, better yet,
<br /> \rho_s(z)\rightarrow\rho_0cos(\theta)<br />
where \rho_0 is some unknown constant with units of C/m^2.
 
turin said:
No typo. One unit of length in z cancels one unit of length in the denom. of C/m^3.

This is misleading (i.e. wrong). The first inequality should be confusing. I would suggest:
<br /> \rho_s(z)=\rho_0z\rightarrow{}\rho_0Rcos(\theta)=bcos(\theta) (C/m^3)<br />
where \rho_0 is some unknown constant that has units of charge-per-volume and R and b have units of length.
Or, better yet,
<br /> \rho_s(z)\rightarrow\rho_0cos(\theta)<br />
where \rho_0 is some unknown constant with units of C/m^2.

That makes much more sense, thank you.
 
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