How can the dolphin reach its home bay while swimming against a river current?

  • Thread starter Thread starter Snoop06
  • Start date Start date
  • Tags Tags
    Physics Relative
AI Thread Summary
To swim directly back to its home bay against a southeast current, the dolphin must adjust its heading to compensate for the current's influence. The solution involves using vector components to analyze the dolphin's swimming speed and the river's current. By determining the east/west and north/south components of both the dolphin's and the current's velocities, the correct angle can be calculated. The discussion highlights the importance of relating the velocities to find the appropriate direction and time needed for the dolphin to reach its destination. Ultimately, understanding these vector relationships simplifies the problem significantly.
Snoop06
Messages
20
Reaction score
0

Homework Statement



A dolphin wants to swim directly back to its home bay, which is 0.77 km due west. It can swim at a speed of 4.49 m/s relative to the water, but a uniform water current flows with speed 2.75 m/s in the southeast direction.

(a) What direction should the dolphin head?

(degrees) N of W

(b) How long does it take the dolphin to swim the 0.77-km distance home?

(min)

Homework Equations


The Attempt at a Solution



I have been trying this for a while now, and have just been getting more and more frustrated. I must be missing something simple but I can't figure it out. I tried assuming that "southeast" meant directly, ie 45*, with no luck. I also tried to somehow get two different equations with the angle in them to set equal to each other but couldn't find a way to do that either. Any help is appreciated.

Thanks,
Justin
 
Physics news on Phys.org
There are 2 ways to solve this (and all these types of problems)... graphically where you solve using the geometry of a triangle... or using components...

Using components... if the angle is theta of the velocity of the dolphin relative to water... the dolphin's east/west velocity is... 4.49 cos(theta). the north south component is 4.49sin(theta)

what is the east/west component of the river's velocity (yes, it is 45 degrees)... what is the north south component?

What can you tell about the sum of the dolphin's north south velocity, and the river's north/south velocity?
 
learningphysics said:
There are 2 ways to solve this (and all these types of problems)... graphically where you solve using the geometry of a triangle... or using components...

Using components... if the angle is theta of the velocity of the dolphin relative to water... the dolphin's east/west velocity is... 4.49 cos(theta). the north south component is 4.49sin(theta)

what is the east/west component of the river's velocity (yes, it is 45 degrees)... what is the north south component?

What can you tell about the sum of the dolphin's north south velocity, and the river's north/south velocity?

Ah I wasn't relating the north/south velocity of the current to the north/south velocity of the dolphin. That makes it all work out with the 45* angle. Thanks for the help :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top