How can the momentum of a thrown rock be calculated with given parameters?

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SUMMARY

The momentum of a thrown rock can be calculated using the formula P = m * v, where P is momentum, m is mass, and v is velocity. In this discussion, a rock with a mass of 1.10 kg was thrown at a launch angle of 39.0° and achieved a calculated velocity of 22.54 m/s, resulting in a momentum of 24.8 kg·m/s. The irregular shape of the rock and its launch height of 0.668 m above ground level are critical factors influencing its trajectory and momentum calculation. Understanding these parameters is essential for accurate momentum analysis in projectile motion.

PREREQUISITES
  • Basic understanding of physics concepts such as momentum and projectile motion.
  • Familiarity with the formula P = m * v for calculating momentum.
  • Knowledge of trigonometry to analyze launch angles in projectile motion.
  • Understanding of gravitational effects on objects in motion.
NEXT STEPS
  • Research "ballistics" to understand the principles governing projectile motion.
  • Study the effects of launch angles on projectile trajectories.
  • Explore the impact of mass and shape on the motion of thrown objects.
  • Learn about energy conservation in projectile motion and its relation to momentum.
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of projectile motion and momentum calculations.

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Homework Statement
A rock of mass 1.10kg and volume 283cm3 is irregular shape. A person throws the rock with a launch angle of 39.0° (above the horizontal) over flat level ground from a height of 0.668m above the ground. Ground level is at an elevation of 138m above sea level. The rock goes 7.40 m down range before it hits the ground. The rock bounces off the ground achieving a maximum height of 12.0cm and traveling an additional 18.0cm down range before coming to rest with a thud. Find the momentum of the rock at the instant it leaves the thrower’s hand.

The attempt at a solution
So what I did was V = √2gx (where x is distance) and I got a velocity of 22.54 m/s. I plugged that into the equation P=m*v to get momentum of 24.8 kgm/s However, I'm not sure I did this right at all.
 
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Welcome to PF.
Hint. Look up "ballistics".
the formula you used is for when the rock is dropped a from rest from a height x, when gravity is the only force. Is that what happened here?

Why is it important that the rock is irregular?
Why is the height above sea level mentioned?
What difference would the angle the rock got thrown make?
 

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