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I How can voltage drop be zero if E-field isn't?

  1. Oct 1, 2016 #1
    Hi.
    I learnt that in an ideal conductor in a circuit, the voltage drop is zero. But how does this agree with the basic definition of voltage
    $$U_{AB}=\int_A^B \vec{E}\cdot d\vec{s}\enspace ?$$
    The electric field inside a conductor only vanishes in static conditions, but in an electric circuit, it makes up the driving force of the current and is obviously nonzero.
     
  2. jcsd
  3. Oct 1, 2016 #2

    vanhees71

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