- #1

alan123hk

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Recently, I've seen several discussion threads here about splitting electric fields. I want to express my opinion. Of course, this is just a calculation method, not a basic physical concept, but it is also useful in some cases, at least not wrong.

The following is an example of the out of a transformer, which also implies the concept of splitting the E field.

The following is a more practical example, assuming that the operating frequency is very low, and the magnetic field in the external space and wires is zero, how to find the displayed value of the voltmeter?

We can write down the voltage loop equations for the left and right sides and solve them. After a long and laborious process of derivation on at least one A4 sheet, I finally came to conclusion ##~V_m=\frac{EMF}{2}\frac{R_2-R_1}{R2+R1}=0.4V~##, but using the concept of splitting electric fields gave immediate results.

It can also be used to evaluate the distribution of charges on the circuit, which is very interesting and practical, such as the following example, I believe it is not far from reality.

Please note that from the bottom 0V to the top 0.4V can be expressed as ##~-0.25+0.9+-0.25=0.4V ##

Sorry, I can only think of these few examples for now.

The following is an example of the out of a transformer, which also implies the concept of splitting the E field.

We can write down the voltage loop equations for the left and right sides and solve them. After a long and laborious process of derivation on at least one A4 sheet, I finally came to conclusion ##~V_m=\frac{EMF}{2}\frac{R_2-R_1}{R2+R1}=0.4V~##, but using the concept of splitting electric fields gave immediate results.

Please note that from the bottom 0V to the top 0.4V can be expressed as ##~-0.25+0.9+-0.25=0.4V ##

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