T7
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Hi,
I appreciate that we can calculate the x-coordinate of the centre of mass of a system of bodies like this:
x = (m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + ... + m_{n}x_{n}) / M
where M is the total mass.
This could be rewritten as
x = \frac {1} {M} \sum_{i=1}^n m_{i}x_{i}
My next step would be to say that
x = \frac {1} {M} \int_{a}^{b} m dx
(I am imagining a scanner sweeping horizontally through an object X and recording its mass at very small intervals).
However, looking in the textbook, it is expressed as
x = \frac {1} {M} \int x dm
I'm a bit of a beginner as far as calculus goes, but it seems to me that\int x dm is not the same as \int m dx.
Looking at the problem geometrically, if you plot m against x, then \int_{a}^{b} m dx will give you an area between the graph of m and the x-axis, whereas \int_{a}^{b} x dm will give you an area between the graph of m and the y-axis.
I appreciate that we can calculate the x-coordinate of the centre of mass of a system of bodies like this:
x = (m_{1}x_{1} + m_{2}x_{2} + m_{3}x_{3} + ... + m_{n}x_{n}) / M
where M is the total mass.
This could be rewritten as
x = \frac {1} {M} \sum_{i=1}^n m_{i}x_{i}
My next step would be to say that
x = \frac {1} {M} \int_{a}^{b} m dx
(I am imagining a scanner sweeping horizontally through an object X and recording its mass at very small intervals).
However, looking in the textbook, it is expressed as
x = \frac {1} {M} \int x dm
I'm a bit of a beginner as far as calculus goes, but it seems to me that\int x dm is not the same as \int m dx.
Looking at the problem geometrically, if you plot m against x, then \int_{a}^{b} m dx will give you an area between the graph of m and the x-axis, whereas \int_{a}^{b} x dm will give you an area between the graph of m and the y-axis.
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