How can we use interpolation to create two functions?

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Homework Help Overview

The discussion revolves around the use of interpolation to create two functions based on a given mathematical context. Participants are exploring how to express a function in terms of other functions and verify certain properties at specified points.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the relationship between the functions involved and how to demonstrate that a constructed function equals zero at specific points. Questions are raised about the meaning and purpose of certain variables and expressions in the context of the problem.

Discussion Status

Some participants are clarifying their understanding of the problem setup and the equations presented. There is an ongoing exploration of how to manipulate the functions and verify the conditions stated in the problem. No consensus has been reached yet, but hints and suggestions have been offered to guide the discussion.

Contextual Notes

Participants are working with specific constraints related to the interpolation problem, including the need to show certain equalities at defined points. The original poster's intent and the clarity of the problem statement are also under scrutiny.

haya
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Homework Statement



[PLAIN]http://im2.gulfup.com/2011-04-01/1301652393881.gif

Homework Equations




how can we do into 2 functions

The Attempt at a Solution



[PLAIN]http://im2.gulfup.com/2011-04-01/1301652475262.gif
 
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I do not understand what you are trying to do with all those L's. Just let x=x0,x1,.,xn to verify the equation.
 
how can i show that ?
 
let
g(x)=-f(x)+p(x)(xn-x)/(xn-x0)+q(x)(x-x0)/(xn-x0)
we want to prove that
g(x)=0 for x=x0,x1,.,xn
given
p(x)-f(x)=0 for x=x0,x1,.,xn-1
q(x)-f(x)=0 for x=x1,x2,.,xn

hint
use the fact that 1=(xn-x)/(xn-x0)+(x-x0)/(xn-x0)

to write g(x) as
g(x)=-f(x)(xn-x)/(xn-x0)-f(x)(x-x0)/(xn-x0)
+p(x)(xn-x)/(xn-x0)+q(x)(x-x0)/(xn-x0)
 

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