How Can XY = 1 and YZ = 1 Prove X = Z?

AI Thread Summary
Given n×n square matrices X, Y, and Z where XY = 1 and YZ = 1, the goal is to prove that X = Z. The initial approach incorrectly assumes that if XY = ZY, then X must equal Z. However, this reasoning fails if Y is singular, as it can lead to multiple solutions. A critical insight is to consider the product XYZ, which can help clarify the relationship between the matrices. Ultimately, the proof requires careful manipulation of the matrix equations rather than relying on assumptions about the placement of Y.
ConeOfIce
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Homework Statement


Suppose one has n×n square matrices X, Y and Z such that
XY = 1and Y Z = 1. Show that it follows that X = Z.

The Attempt at a Solution


Now I know if the equatoins had been XY and ZY I would do this:

XY=ZY -> XY-ZY=0 -> Y(X-Z)=0 -> X-Z=0 -> X=Z

I was wondering if this holds when the Y is on opposite sides of the other matrices?

Thanks in advanced!
 
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ConeOfIce said:

Homework Statement


Suppose one has n×n square matrices X, Y and Z such that
XY = 1and Y Z = 1. Show that it follows that X = Z.

The Attempt at a Solution


Now I know if the equatoins had been XY and ZY I would do this:

XY=ZY -> XY-ZY=0 -> Y(X-Z)=0 -> X-Z=0 -> X=Z

I was wondering if this holds when the Y is on opposite sides of the other matrices?

Thanks in advanced!

I am sure you would have better luck in the math forums.

Casey
 
You are throwing away a lot of information in going from XY=1 and ZY=1 to XY=ZY. If Y is singular, there are infinitely many distinct matrices X and Z for which XY=ZY. With matrices and vectors, the step (X-Z)Y = 0 to X-Z=0 is in general invalid.

Hint: What is XYZ?
 
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