How Can You Determine the Wavefunction ψ(r) from Electron Density |\psi(r)|^2?

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I have a 3 dimensional orbital-specfic electron density function ( |\psi(r)|2 ) for all relevant r values. How would I go about finding the corresponding \psi(r)? I know it would be something related to a Fourier transform, I'm just unsure about how to go about performing it in mathematica or matlab. Can anyone give me any pointers?
 
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You can't. Probability density carries less information than wave function. Many wave functions may lead to the same probability density. Even Fourier can't help.
 
If it's as simple as you're making it sound, with no spin dependence or (θ,φ) dependence, just r dependence, then the wavefunction ψ for a nondegenerate stationary state can always be chosen to be real. (Proof: by time-reversal invariance ψ* is also a solution, so if there's only one solution then ψ = ψ*.) So if that's the case, just take the square root.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
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