How Can You Find a Closed Form for the Series x + 2x² + 3x³ + 4x⁴ + ...?

AI Thread Summary
The discussion focuses on finding a closed form for the series x + 2x² + 3x³ + 4x⁴ + ... expressed as the sum ∑(n=1 to ∞) nx^n. Participants suggest differentiating the formula for the infinite geometric series, ∑(n=0 to ∞) x^n = 1/(1-x), to derive a solution. They recommend combining the original series S with xS to simplify it into a geometric progression. This approach is identified as a method for handling arithmetic geometric progressions (AGP). The conversation emphasizes the utility of manipulation techniques in series summation.
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Homework Statement



I want to find a closed form formula for:

x+2x^2+3x^3+4x^4+\ldots

I know that this can be written as:

\sum_{n=1}^{\infty}nx^n

but I would like to have a closed formula for this.

The formula for an infinite geometric series is:
\sum_{n=0}^{\infty}x^n = \frac{1}{1-x}

Which is somewhat close but the series in question is not exactly geometric.

How do I go about doing this?
 
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Try differentiating the formula for the geometric series.
 
Also, the usual "trick" for deriving geometric series also works for that one -- combine the original series S with the series xS to produce something simpler.
 
this sort of series is called an arithmetic geometric progression (AGP) or something...like someone said, multiply by x and then subtract to get a simple geometric progression...in this case you could even divide by x
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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